C Program to Solve Sum of Series 1-x2/2! +x4/4!-x6/6!+x8/8!-x10/10!

/*Calculate Sum of Series:
	Sum=1-x2/2! +x4/4!-x6/6!+x8/8!-x10/10! (x2 means : x power 2) 
*/

#include <stdio.h>
#include <math.h>

main()
{
    int counter,f_coun;
    float sum=0,x,power,fact;

    printf("\tEQUATION SERIES : 1- X^2/2! + X^4/4! - X^6/6! + X^8/8! - X^10/10!");

    printf("\n\tENTER VALUE OF X : ");
    scanf("%f",&x);

    for(counter=0, power=0; power<=10; counter++,power=power+2)
    {
        fact=1;
        //Factorial of POWER value.
        for(f_coun=power; f_coun>=1; f_coun--)
            fact *= f_coun;
        //The main equation for sum of series is...
        sum=sum+(pow(-1,counter)*(pow(x,power)/fact));
    }

    printf("SUM : %f",sum);

}